4^x-1(0.5)^3-2x=(1/8)^x

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Solution for 4^x-1(0.5)^3-2x=(1/8)^x equation: 



4^x-1(0.5)^3-2x=(1/8)^x

We move all terms to the left:

4^x-1(0.5)^3-2x-((1/8)^x)=0



Domain of the equation: 8)^x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

4^x-2x-((+1/8)^x)-1(0.5)^3=0

We add all the numbers together, and all the variables

-2x+4^x-((+1/8)^x)-0.125=0

We multiply all the terms by the denominator


-2x*8)^x)+4^x*8)^x)-((+1-(0.125)*8)^x)=0

Wy multiply elements

-1024x^4=0

We do not support expression: x^4

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